26=x^2+9x

Solution for 26=x^2+9x equation:

26=x^2+9x

We move all terms to the left:

26-(x^2+9x)=0

We get rid of parentheses

-x^2-9x+26=0

We add all the numbers together, and all the variables

-1x^2-9x+26=0

a = -1; b = -9; c = +26;
Δ = b2-4ac
Δ = -92-4·(-1)·26
Δ = 185
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{185}}{2*-1}=\frac{9-\sqrt{185}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{185}}{2*-1}=\frac{9+\sqrt{185}}{-2}
$